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Andrew Cooper
56b77d7db0
With Python 3.11, the following is emitted during a build:
tools/include/xen-foreign/mkheader.py:162: DeprecationWarning: invalid escape sequence '\s'
regex = "#define\s+%s\\b" % define;
tools/include/xen-foreign/mkheader.py:177: DeprecationWarning: invalid escape sequence '\*'
input = re.compile("/\*(.*?)\*/", re.S).sub("", input)
tools/include/xen-foreign/mkheader.py:178: DeprecationWarning: invalid escape sequence '\s'
input = re.compile("\n\s*\n", re.S).sub("\n", input);
tools/include/xen-foreign/mkheader.py:182: DeprecationWarning: invalid escape sequence '\s'
regex = "union\s+%s\s*\{(.*?)\n\};" % union;
tools/include/xen-foreign/mkheader.py:192: DeprecationWarning: invalid escape sequence '\s'
regex = "(?:#ifdef ([A-Z_]+))?\nstruct\s+%s\s*\{(.*?)\n\};" % struct;
tools/include/xen-foreign/mkheader.py:218: DeprecationWarning: invalid escape sequence '\s'
output = re.sub("\\b(union\s+%s)\\b" % union, "\\1_%s" % arch, output);
tools/include/xen-foreign/mkheader.py:222: DeprecationWarning: invalid escape sequence '\s'
output = re.sub("\\b(struct\s+%s)\\b" % struct, "\\1_%s" % arch, output);
Python regexes should use raw strings. Convert all regexes, and drop escaped
backslashes. Note that regular escape sequences are interpreted normally when
parsing a regex, so \n even in a raw-string regex is a newline.
No functional change.
Signed-off-by: Andrew Cooper <andrew.cooper3@citrix.com>
Reviewed-by: Anthony PERARD <anthony.perard@vates.tech>
Release-Acked-by: Oleksii Kurochko <oleksii.kurochko@gmail.com>