xen/gen_hypercall: Fix if indent

On x86, the opening if of call_handlers_*() is indented 4 spaces which
breaks alignment.  The alignment is broken by printf("    "), but
that actually aligns ARM's opening "if ( likely() )".  Move the indent
to the if that needs it.

This results in x86 hypercall-defs.h changes like:

 #define call_handlers_hvm64(num, ret, a1, a2, a3, a4, a5) \
 ({ \
     uint64_t mask = (num) > 63 ? 0 : 1ULL << (num); \
-        if ( likely(mask & ((1ULL << __HYPERVISOR_vcpu_op) | (1ULL << __HYPERVISOR_event_channel_op))) ) \
+    if ( likely(mask & ((1ULL << __HYPERVISOR_vcpu_op) | (1ULL << __HYPERVISOR_event_channel_op))) ) \
     { \
         if ( (num) == __HYPERVISOR_vcpu_op ) \

ARM's hypercall-defs.h does not change.

Signed-off-by: Jason Andryuk <jason.andryuk@amd.com>
Reviewed-by: Jan Beulich <jbeulich@suse.com>
This commit is contained in:
Jason Andryuk authored and Jan Beulich committed 2025-12-08 15:51:41 +01:00
1 parent 9dc90fd48d
commit cc7095a82d
1 file changed
+2 -2
+2 -2
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@@ -266,7 +266,7 @@ END {
printf("({ \\\n");
if (need_mask)
printf(" uint64_t mask = (num) > 63 ? 0 : 1ULL << (num); \\\n");
printf(" ");
for (pl = 1; pl <= n_prios[ca]; pl++) {
if (prios[ca, p_list[pl]] > 1) {
if (pl < n_prios[ca]) {
@@ -292,7 +292,7 @@ END {
} else {
for (i = 1; i <= nc; i++)
if (call[i] == ca && call_prio[i] == p_list[pl]) {
printf("if ( likely((num) == __HYPERVISOR_%s) ) \\\n", fn[call_fn[i]]);
printf(" if ( likely((num) == __HYPERVISOR_%s) ) \\\n", fn[call_fn[i]]);
do_call(call_fn[i], call_p[i]);
}
}
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