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scratch_alloc() set scratch_start to the last byte of the current allocation. The value of scratch_start is then reused as is (if it is already aligned) in the next allocation. This result in a potential reuse of the last byte of the previous allocation. Signed-off-by: Anthony PERARD <anthony.perard@citrix.com> Reviewed-by: Jan Beulich <jbeulich@suse.com>